declare array with specific characters

[saharul]

hi ,

how to write code to declare 6 arrays and each array can only has 4 characters of binary numbers .The binary numbers will be generated by random.

for example i need four arrays that consists:-

array1 has '0110'
array2 has '1000'
array3 has '0110'
array4 has '1000'

if i write

char array[6]

it prepares 6 arrays but each array can have more than 4 characters,

many thanks

[stefan.filipovic]

Hi,

I made an example project and examples of these functions you are referring to.

Please find the project in the attachment.

Kind regards,

[saharul]

Thank you Stefan.
your code of conversion to binary numbers worked well.
But after doing cross over, and i read back the decimal value after conversion and display to GLCD, it displayed unknown character.

i tried this code

Code: Select all

.......................
int value;char txt;

....................
value=char1;
........................
Int To Str(value,txt);
Glcd_Write_Text(txt,77,7,2);

do i need to write special conversion from binary to decimal using "pow" for each binary bits.

Many thanks Stefan

[stefan.filipovic]

Hi,

I'm sorry but I'm afraid that I have not understood you correctly.

Could you please share the whole code which explains what you intended to do?

I understand that you want to display something on the GLCD, but I can't see exactly how you have been trying to do that.

Kind regards,

[saharul]

Thank you for your reply,

I meant after doing cross over/exhange bits , how do I finally display the final result in decimal not in binary?

Many thanks

[stefan.filipovic]

Hi,

If you want to convert a string with bits to the string with a decimal value, just call the function StrBitsToUChar from the project which I attached before, and after that call the function BytoToStr from the Conversions library, as shown below.

Code: Select all

unsigned char num1;
char array[] = "01010101";
StrBitsToUChar(array, &num1);
ByteToStr(num1, array);

Kind regards,