MikroElektronika Forum

Posted: **05 Dec 2010 10:47**

Hello!

Let's just say that I'm kinda new with mikroC, I'm using 8.2 version and, in the following example
C:\Program Files\Mikroelektronika\mikroC\Examples\EasyPic5\P16F887\ADC_on_LCD
there is one line that I can't understand:

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  ADCON1     = 0x82;                       // configure VDD as Vref, and analog channels

because in pic's datasheet ADCON1 register:

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bit 7 ADFM: A/D Conversion Result Format Select bit
1 = Right justified
0 = Left justified
bit 6 Unimplemented: Read as ‘0’
bit 5 VCFG1: Voltage Reference bit
1 = VREF- pin
0 = VSS
bit 4 VCFG0: Voltage Reference bit
1 = VREF+ pin
0 = VDD
bit 3-0 Unimplemented: Read as ‘0’

so why do you assign 1 to a 0 bit, and why do you need the "Right justified" option??

Thanks for the help!

Posted: **06 Dec 2010 11:42**

The output from the ADC it 10-bit so you have the choice of acquiring the data like this: nnnnnnnn nn000000 (LJ) or like this: 000000nn nnnnnnnn (RJ), both instances will fill two bytes. Assuming that you are then going to do some calculations with those two bytes, which do you think would be easier, LJ or RJ?

MikroElektronika Forum

simple one: adc_on_lcd, why is adcon1=0x82??

simple one: adc_on_lcd, why is adcon1=0x82??

Re: simple one: adc_on_lcd, why is adcon1=0x82??